x^2+4.8x-0.096=0

Solution for x^2+4.8x-0.096=0 equation:

x^2+4.8x-0.096=0

a = 1; b = 4.8; c = -0.096;
Δ = b2-4ac
Δ = 4.82-4·1·(-0.096)
Δ = 23.424
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.8)-\sqrt{23.424}}{2*1}=\frac{-4.8-\sqrt{23.424}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.8)+\sqrt{23.424}}{2*1}=\frac{-4.8+\sqrt{23.424}}{2}
$